Is there any way I can turn an integer like 26 into an ascii character without doing 127 case statements to see what character the number 26 represents? Using C++. Thanks!
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Is there any way I can turn an integer like 26 into an ascii character without doing 127 case statements to see what character the number 26 represents? Using C++. Thanks!
Well there is an itoa function that converts an integer to either a string or acii characters, i forget which. The syntax is itoa(number,char *, radix), wherer number is the number you want to convert, car * is the C-style string you want to convert it to, and radix is the base(10 for our case). Hope this helps.
Edit: Most c++ compilers may not support this function since it is not ANSI standard C(or c++).
That's not what he wants, I don't think. Well, in C++ anyway, ints and chars are the same basic type, so you could just do something like ('A' + x - 1). But that's dependant on the charset. The absolute safest way is going to be with the case statement for sure. (or an array would probably be better.. i don't know how a case is implemented, maybe it's the same thing) Like this:
char bob[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
char ch = bob[x-1];
Sounds like he just needs to cast...
int ascii = 26;
char ch = (char) ascii;
Oh I see.. I was thinking that he wanted the number 26 to correspond with 'z'. Confused me, since there are 26 letters in the alphabet... :D
if you are doing assignment for ECE628, PM me bcoz i have wrote the program to solve problem #4 (took me like 10 hrs) >:-(
But i dont hve the solution for #3 yet :P
nt
thats just a first draft, but it works perfect so far, you can use it if you like. But i suggest using itoa() unless this is for some assignment. Also dont confuse char with int (notice i did not need to use any type casts), they are really the same thing, you can use an integer array to store a string if you want, you just have to make sure each number in the array is a real ascii number, look up an ascii table, the numbers start with 30h and end on 39h
int and char aren't really the same: sizeof(char) tends to be one byte, sizeof(int) tends to be 4. Don't try to store ints in characters. You don't have to do casts because they happen automatically.
Why void main() ?
A char is typically 1 byte (8 bits) and an int is 32 bits or 4 bytes, yes they are different sizes, but what people get confused about is that char's are reserved ONLY for letters and ints only for integers, its completely arbitrary and its up to the programmers to use the data types as he or she wishes. That is what I was trying to explain.
why void main()?
You can make up your own function name and parameters, I merely showed you one way how to convert a number into a string, apparently it was now what the guy asked for, perhaps he can be more specific in the future.
hmmm but void main() isn't the c++ standard method, meaning void main() could stop working some day. To be sure you should ALWAYS have int as the return time for main even if you dont need to return anything.
couldn't you just make a for loop?
Code:char num=0;
for(int i=0;i<200;i++)
{
cout << i << endl;
num=i;
}
im sorry i posted the example
Just finished reading this thread, and I gotta say it was annoying to not know what everyone was talking about because you edited your post and deleted the example. :(Quote:
Originally posted by lms
im sorry i posted the example