Functions

[f15e]

Is it possible to pass a string by reference?
For example, void SomeFunction(string&, string&);
I know this isn't correct but how can I pass strings by reference if at all possible?

[dighn]

yes of course you can pass strings by reference. eg

using std::string;

void foo(string& bar)
{
bar = "barfoo";
}

void foobar()
{
string fubar = "foobar";
foo(fubar);
//now fubar is "barfoo";
}

[Oliwa]

Why does everyone use Foo, Bar, and Foobar in examples?

[f15e]

That's funny Oliwa. I have noticed that to when I read some of the other posts.

[krack_it_up]

hehe... usually if you have to ask how to do something... it is FUBR.

[biosx]

That's FUBAR, not FUBR... I don't like how people use foobar b/c when you spell it differently it loses all it's meaning.

I learned about FUBAR in my cyperpunk fakebook I got from my stepmom when I was like 12.. Who knows why she bought me that book.

[dighn]

it's like an unspoken rule to use foobar in your code examples although i think i over did it LOL

btw it's not "fubar"

[!shira!]

Originally posted by dighn
yes of course you can pass strings by reference. eg

using std::string;

void foo(string& bar)
{
bar = "barfoo";
}

void foobar()
{
string fubar = "foobar";
foo(fubar);
//now fubar is "barfoo";
}

wouldn't it be
void foo(string* bar)
{
bar = "barfoo";
}
void foobar()
{
string fubar = "foobar";
foo(&fubar);
}

[dighn]

Originally posted by !shira!


wouldn't it be
void foo(string* bar)
{
bar = "barfoo";
}
void foobar()
{
string fubar = "foobar";
foo(&fubar);
}

sorry but no
first of all that's using pointers
secondly bar = "barfoo" is illegal. it should be *bar = "barfoo";
with that little change it accomplishes the same thing but that's using pointers instead of references (pointer is type*, reference is type&) which was what he asked for.

[!shira!]

I get it about refrences now and you were right about the illegal pointer call

The C programming language SE is a handy book (much easier reade than the first)